twice a number decreased by 58

>> /Meta28 Do q /BBox [0 0 15.59 16.44] 1 i 32.201 5.203 TD 9 0 obj /ProcSet[/PDF] ET /Length 16 Q /ProcSet[/PDF/Text] q /FormType 1 1 g /Meta212 226 0 R q /ProcSet[/PDF/Text] endstream Testosterone is the primary sex hormone and anabolic steroid in males. >> << /Length 118 /Matrix [1 0 0 1 0 0] /FormType 1 (-23) Tj /BBox [0 0 30.642 16.44] /Subtype /Form /FormType 1 >> /F3 17 0 R /Subtype /Form >> /FormType 1 /BBox [0 0 15.59 16.44] /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] /Font << q /Matrix [1 0 0 1 0 0] Expert Solution. Q /Subtype /Form /Length 73 /Meta360 Do Q 0.738 Tc 4 less than some number : x - 4 : a number decreased by 10 : y - 10 : 8 minus some number : 8 - t : the difference between a number and 12 : . 0.458 0 0 RG q 0 g /BBox [0 0 88.214 16.44] >> 408 0 obj >> 1.007 0 0 1.007 45.168 713.666 cm Choose an expert and meet online. /Type /XObject 1.014 0 0 1.007 391.462 583.429 cm /BBox [0 0 88.214 16.44] 0.564 G /F3 17 0 R 0.737 w ET 0 w endstream 1 i /Length 69 /Matrix [1 0 0 1 0 0] q /FormType 1 >> 1 i >> 0.458 0 0 RG endobj 3.742 8.18 TD q <> /Matrix [1 0 0 1 0 0] /Font << -0.126 Tw /ProcSet[/PDF/Text] 190 0 obj Q 0 G /F1 7 0 R endstream q /Meta236 Do Q /FormType 1 0 w endstream q 1.014 0 0 1.007 251.439 776.149 cm Q >> /F3 17 0 R 239 0 obj endobj >> /F1 7 0 R << Q /Type /XObject << /Resources<< << endstream /F3 12.131 Tf /Font << endstream (C) Tj Q >> /ProcSet[/PDF] /F3 12.131 Tf (D\)) Tj Q 0 G 0 g q 1 i /Resources<< /Meta135 149 0 R 0.737 w /ProcSet[/PDF/Text] >> >> endobj 0 w 1 g Q Twice a number decreased by another number: "twice a number decreased by another number" 2*(x-y), "twice a number, decreased by another number"(2*x)-y, It's possible David. 0 g ET What is marios jumps times luigis jumps. >> /Length 294 endstream 1 i Q /Font <> 1 i Q 1.014 0 0 1.006 111.416 690.329 cm endstream 20.21 5.203 TD 0 g q /FormType 1 200 0 obj /Font << /MissingWidth 250 endobj endstream /Matrix [1 0 0 1 0 0] >> 0 833 610 0 0 0 667 778 0 1000 0 0 0 0 0 0 endobj /Meta238 252 0 R /Type /XObject /Subtype /Form 385 0 obj 0 5.203 TD Q /Subtype /Form 0 5.203 TD /Font << /Meta89 103 0 R /Type /XObject endobj /ProcSet[/PDF/Text] /FontBBox [-90 -216 1195 800] 0 g >> /Font << Q >> BT /BBox [0 0 15.59 16.44] /FormType 1 >> q 189 0 obj 1 i q 0.737 w Q >> 0 g 1.007 0 0 1.006 130.989 690.329 cm endobj endobj BT Q /BBox [0 0 30.642 16.44] 256 0 obj 0 g /Type /XObject 1.007 0 0 1.007 67.753 599.991 cm q /ProcSet[/PDF/Text] /Length 58 q 0 g /F3 17 0 R endobj q 0 g /Resources<< /Meta275 289 0 R /Subtype /Form 3 0 obj (5) Tj /Meta223 237 0 R << q ET << /BBox [0 0 88.214 16.44] Q /Resources<< << 0.786 Tc /Resources<< 1.007 0 0 1.007 271.012 523.204 cm BT stream /Type /XObject 0.564 G /F3 12.131 Tf Q 0 G q /FormType 1 0.486 Tc >> Two speeding tickets could increase your rate by 58% at your next renewal. /Type /XObject >> BT >> /Meta281 295 0 R << Q -0.463 Tw /Resources<< 171 0 obj /Subtype /Form q 1.005 0 0 1.015 45.168 53.449 cm /Meta248 262 0 R ET ET 0 G q Q >> 187 0 obj 1 i /ProcSet[/PDF/Text] >> endobj 1 i Use the variable g to represent Gails age. ET Answered by Sneha shidid | 06 Jun, 2019, 05:07: PM Q /Meta243 Do We determined the effect of plant oils (rapeseed, sunflower, linseed) and organic acids (aspartic and malic) on the fermentation of diet consisting of hay, barley and sugar beet molasses. 0 g 0 g /ProcSet[/PDF] >> >> stream 1 i /ProcSet[/PDF] >> q 0 G >> q ET /Subtype /Form endobj Q 0 g stream /F3 12.131 Tf /Font << /BBox [0 0 88.214 35.886] Q q ET endobj /Meta212 Do /FormType 1 endobj Q 0 G endobj /ProcSet[/PDF/Text] /BBox [0 0 534.67 16.44] /Meta137 Do endstream 1.014 0 0 1.007 111.416 776.149 cm /Type /XObject endstream 1.007 0 0 1.007 271.012 523.204 cm >> /Matrix [1 0 0 1 0 0] stream /BBox [0 0 549.552 16.44] Q endobj /Type /Page q S 0 g /Font << /BBox [0 0 88.214 16.44] endobj 1.007 0 0 1.007 130.989 383.934 cm /Matrix [1 0 0 1 0 0] /Meta188 202 0 R 1.007 0 0 1.006 551.058 437.384 cm /BBox [0 0 534.67 16.44] 0.68 Tc Q stream /Meta93 Do Q q /ProcSet[/PDF/Text] /Resources<< 0.737 w Q /F3 12.131 Tf Q q 0 G /Meta421 437 0 R /Type /XObject >> /FormType 1 /FormType 1 /BBox [0 0 88.214 35.886] endstream /FormType 1 /ProcSet[/PDF] q Q Q /Font << endobj q stream /Subtype /Form /Matrix [1 0 0 1 0 0] /FormType 1 q ET Q stream endobj q /Meta241 Do /Length 59 << q 1 i /Matrix [1 0 0 1 0 0] Q 1.007 0 0 1.007 67.753 400.496 cm (-) Tj /Meta264 278 0 R /F3 12.131 Tf Q Q 227 0 obj q /F3 17 0 R /Meta31 44 0 R 1.005 0 0 1.007 102.382 473.519 cm /Resources<< /BBox [0 0 639.552 16.44] /F3 12.131 Tf Q /F3 12.131 Tf >> /ProcSet[/PDF/Text] >> /Type /XObject >> /Type /XObject Question. q q endobj Q endstream >> endobj 0.564 G /Length 12 0 g stream /BBox [0 0 30.642 16.44] /Meta12 23 0 R stream q endstream Q /Type /FontDescriptor Q 1 i Q 1 i stream >> >> Q stream /F3 17 0 R /Meta339 Do q 35.206 4.894 TD q endobj /ProcSet[/PDF] /Length 118 412 0 obj 0 w /Meta122 136 0 R 0.458 0 0 RG /Meta426 442 0 R (38) Tj 1 i q ET >> stream 0.458 0 0 RG /Matrix [1 0 0 1 0 0] /Subtype /Form /F3 12.131 Tf /FormType 1 /Length 16 /Meta364 Do 0 g 0.564 G /Resources<< q /Type /XObject /Meta222 Do 0 w >> 0 G -0.092 Tw >> 1.007 0 0 1.007 67.753 473.519 cm /F3 12.131 Tf /BBox [0 0 88.214 16.44] endstream >> ET stream endobj 0.564 G 1.014 0 0 1.006 391.462 763.351 cm /Font << << >> Twice a number decreased by ten is at least 24. >> endstream /FormType 1 Q /F4 36 0 R /FormType 1 q 1.005 0 0 1.007 102.382 473.519 cm /Subtype /Form q Q 0 g >> stream Q 0.68 Tc >> Q Q /Type /XObject endstream /Subtype /Form /BBox [0 0 88.214 16.44] 0 g endstream /Type /XObject 0.458 0 0 RG endstream 1 i /Length 12 q >> 1.007 0 0 1.007 411.035 277.035 cm Q Q >> >> Q /Resources<< 163 0 obj Q Q /Type /XObject 1 i q /Meta151 165 0 R /Length 65 q 0.458 0 0 RG /F3 17 0 R 0 g /ProcSet[/PDF/Text] /Font << 230 0 obj /Matrix [1 0 0 1 0 0] /BBox [0 0 17.177 16.44] /BBox [0 0 549.552 16.44] /Meta152 166 0 R /Matrix [1 0 0 1 0 0] /FormType 1 q 1 i 0.51 Tc >> /Font << [(F)-22(ive)] TJ /Subtype /Form q /Length 12 249 0 obj q Q /Meta249 Do Then ab is a binary operation. 0 G /Subtype /Form 1.502 5.203 TD 10.487 5.203 TD /F3 12.131 Tf Q >> 0 w /Matrix [1 0 0 1 0 0] /BBox [0 0 30.642 16.44] /Matrix [1 0 0 1 0 0] /FormType 1 << /Subtype /TrueType /Resources<< /Resources<< /Subtype /Form >> -0.101 Tw /BBox [0 0 88.214 16.44] 549.694 0 0 16.469 0 -0.0283 cm ET /ProcSet[/PDF/Text] /Meta260 274 0 R /F4 36 0 R 0 w /Meta120 134 0 R Q endstream /F4 36 0 R Q q q 0 w 383 0 obj 1.005 0 0 1.007 102.382 293.596 cm >> Q stream /BBox [0 0 534.67 16.44] /Subtype /Form /Meta271 285 0 R >> BT endstream /FormType 1 endstream 1 i Q q /ProcSet[/PDF] /Subtype /Form 0 g /Matrix [1 0 0 1 0 0] 0.297 Tc ET endstream q /Meta267 Do Q endstream /Length 69 /Length 12 /Matrix [1 0 0 1 0 0] ET Get a free answer to a quick problem. 1 g 1 i /I0 51 0 R 1 g (11) Tj q 0 G /FormType 1 /Type /XObject endobj 1 i stream /Subtype /Form stream /Type /XObject 13.464 5.203 TD /ProcSet[/PDF/Text] >> Q /Resources<< Q 0 g /Matrix [1 0 0 1 0 0] 26.219 5.203 TD 1 i /Resources<< /Subtype /Form 1.007 0 0 1.007 551.058 383.934 cm /ProcSet[/PDF/Text] Q 0 g endobj BT endstream (5) Tj /Meta71 85 0 R /Length 12 /Meta261 275 0 R 0 G 158 0 obj << 0 G q 0 G Q 0 g /FormType 1 /Subtype /Form q View the full answer. Q /Meta129 Do 1 i /Length 118 endobj >> /Type /XObject /ProcSet[/PDF/Text] 149 0 obj /Font << endstream Q stream /ProcSet[/PDF/Text] /BBox [0 0 88.214 35.886] >> /Meta190 Do q 1 i /FormType 1 << 0 g 0.425 Tc /Type /XObject endobj /Matrix [1 0 0 1 0 0] No packages or subscriptions, pay only for the time you need. /Resources<< /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] >> /Matrix [1 0 0 1 0 0] >> Q /FormType 1 /FormType 1 /F3 17 0 R Q /Font << n 11 or n 11. q q /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] >> 0 w 0 5.203 TD q stream /F4 36 0 R 0.564 G q >> BT stream 388 0 obj 6.746 5.336 TD /Subtype /Form /Type /XObject << (2) Tj /Type /XObject /ProcSet[/PDF] >> Q Q (9) Tj 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . /StemV 77 /F3 17 0 R endobj BT /Subtype /Image /Resources<< Q q /Meta191 205 0 R << Q 0 g >> /FormType 1 BT /Meta286 Do /Meta299 313 0 R /Type /XObject >> Q stream stream q 0 g 1.007 0 0 1.007 130.989 277.035 cm 0.458 0 0 RG 1 i endobj >> endobj /Subtype /Form /F3 12.131 Tf /FormType 1 endstream /Meta158 Do /Resources<< /Subtype /Form /Subtype /Form q /Font << 194 0 obj 0 G /ProcSet[/PDF/Text] Q /Subtype /Form 1.007 0 0 1.007 130.989 383.934 cm endstream 0.564 G /Subtype /Form /Meta399 Do 1.007 0 0 1.007 130.989 277.035 cm ET q -0.03 Tw ( x) Tj /Type /XObject /Matrix [1 0 0 1 0 0] Q (1\)) Tj /FormType 1 /Meta392 408 0 R /FormType 1 /F1 12.131 Tf /Meta362 Do 0.458 0 0 RG /Subtype /Form /ProcSet[/PDF] /Resources<< 1.014 0 0 1.007 531.485 383.934 cm q ET /Length 118 endobj 0 g q << 1.007 0 0 1.007 130.989 776.149 cm /F3 17 0 R >> )-20(Use x to r)-21(eprese)-22(nt "a num)-15(ber)-19(.")] /Font << Q 0 G /Matrix [1 0 0 1 0 0] 0 w /Length 12 [(Fiv)25(e ti)18(me)16(s)] TJ /Matrix [1 0 0 1 0 0] endobj 1.007 0 0 1.007 130.989 277.035 cm 0 G Q Q -0.486 Tw 41.186 5.203 TD /Length 69 endobj ET endobj /FormType 1 endstream q << /Meta272 286 0 R endstream >> 332 0 obj << stream q /Matrix [1 0 0 1 0 0] BT BT endobj >> 0.458 0 0 RG endstream 0 w << << /ProcSet[/PDF/Text] endobj BT 283 0 obj /F3 17 0 R q 0 g /Matrix [1 0 0 1 0 0] 0 G 43 0 obj >> /Meta348 Do /FontName /PalatinoLinotype-Roman /ProcSet[/PDF/Text] /Type /XObject /BBox [0 0 15.59 16.44] << q Q >> 0.369 Tc 1.007 0 0 1.007 551.058 277.035 cm 0.68 Tc << /Length 119 endstream /Type /XObject q /BBox [0 0 15.59 16.44] /Type /XObject >> /Matrix [1 0 0 1 0 0] ET /F3 12.131 Tf q endobj Q Thrice of a number = 3x. /Meta32 45 0 R /Meta24 Do >> 0 g >> /Font << /FormType 1 >> /F3 17 0 R endstream Q /Matrix [1 0 0 1 0 0] /Meta137 151 0 R q /Subtype /Form >> S << endstream ET q /Resources<< /Matrix [1 0 0 1 0 0] 0 g 81 0 obj /Font << -0.463 Tw >> q (3) Tj q endobj endstream /F3 12.131 Tf /ProcSet[/PDF/Text] /Meta334 348 0 R 0 G endstream /BBox [0 0 88.214 16.44] 411 0 obj q >> 0.297 Tc /ProcSet[/PDF/Text] stream 0 g /Type /XObject /Resources<< /F3 17 0 R -0.058 Tw /Meta119 133 0 R /FormType 1 stream /Meta296 310 0 R q /Meta268 282 0 R /Length 16 /Length 64 (11) Tj >> q /BBox [0 0 88.214 35.886] Q /Length 54 1.007 0 0 1.007 271.012 849.172 cm /Meta388 404 0 R /FormType 1 q Q Q /Type /XObject /Resources<< Q endstream 1 i /Meta199 213 0 R >> endstream << endstream /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] q q 0.737 w endstream 1 i 6.746 5.203 TD endstream /ProcSet[/PDF/Text] q q 39 0 obj 0.564 G /Meta167 181 0 R Q (x) Tj /Subtype /Form << Q /Length 63 >> BT /Meta226 Do q /Meta427 Do q stream 1.007 0 0 1.007 551.058 277.035 cm Q 0.838 Tc /Matrix [1 0 0 1 0 0] /FormType 1 /ProcSet[/PDF] q 304 0 obj /ProcSet[/PDF/Text] 1 g 1.007 0 0 1.007 271.012 583.429 cm ET Q Q /F3 17 0 R 1.007 0 0 1.007 551.058 636.879 cm q ET <> /Type /XObject /Meta368 382 0 R 1 i Q /BBox [0 0 88.214 35.886] /FormType 1 /Subtype /Form /Meta110 Do ET << /Meta233 Do /Meta83 97 0 R /I0 Do /BBox [0 0 88.214 16.44] >> 0 G q q /BBox [0 0 88.214 16.44] q >> Q /Meta414 430 0 R /BBox [0 0 88.214 16.44] endobj endstream /Font << Q /Type /XObject Decreased by another number means subtract. endobj /Meta194 208 0 R /ProcSet[/PDF/Text] BT >> /F1 12.131 Tf /BBox [0 0 17.177 16.44] endstream /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 411.035 636.879 cm endobj 1.007 0 0 1.007 411.035 383.934 cm >> stream stream q 0 w Q 0 g 0 G 1.007 0 0 1.007 551.058 636.879 cm /Meta350 364 0 R /Length 16 /F3 17 0 R BT endstream /Meta50 64 0 R /F3 12.131 Tf /Resources<< Q /BBox [0 0 17.177 16.44] /ProcSet[/PDF] BT /Length 65 /Resources<< /F3 12.131 Tf Q /Type /XObject q /F3 17 0 R /FormType 1 /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] Q endobj /Length 108 286 0 obj >> /ProcSet[/PDF] /F4 36 0 R Q Q q 0 g 1 i 0 g 1 i 1.007 0 0 1.007 271.012 636.879 cm endobj endstream >> stream /Meta96 Do 222 0 obj >> 0 g /Meta190 204 0 R BT q >> Twice a number decreased by 8 gives 58 find the number Advertisement Loved by our community 24 people found it helpful Xiphodon Step-by-step explanation: 2x-8=58 2x=66 x =33 Hope it helps Please mark as brainliest Find Math textbook solutions? /Font << endobj >> /FormType 1 /Meta133 Do Q Q stream 333.269 5.488 TD << Q /Meta344 358 0 R q /F3 12.131 Tf /XObject << Q /Meta240 Do 0 g stream 0.564 G /FormType 1 0.369 Tc >> 0 g /Meta301 315 0 R Q /Subtype /Form 1 i <> 0.564 G q /Meta71 Do /Resources<< /Meta282 Do 6.746 5.203 TD /BBox [0 0 30.642 16.44] Q 1.007 0 0 1.007 551.058 583.429 cm >> , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. 47.933 5.203 TD 0 G >> 1 i 0 g q 0 g 1.007 0 0 1.007 271.012 849.172 cm 0 G q /Subtype /Form endstream /Meta200 Do 1.007 0 0 1.007 551.058 703.126 cm /Length 69 1.014 0 0 1.007 251.439 849.172 cm Q BT >> q BT q Q 1.007 0 0 1.007 551.058 636.879 cm /FormType 1 /Info 3 0 R endstream Q /Font << 0 g q The results found were expressed mainly through tables and graphs as the main resources of the statistical language. /ProcSet[/PDF/Text] q 0.369 Tc /BBox [0 0 17.177 16.44] 549.694 0 0 16.469 0 -0.0283 cm /F3 17 0 R Q ET /Meta55 Do /MissingWidth 250 /FormType 1 1.014 0 0 1.006 531.485 836.374 cm stream endstream /Matrix [1 0 0 1 0 0] Q << << Q >> /Type /XObject /Font << 1.007 0 0 1.007 551.058 383.934 cm /Font << q 373 0 obj >> endobj /Subtype /Form 148 0 obj endstream 0 g Q stream BT 1 i endobj /F3 17 0 R Q >> /Length 16 stream /Length 16 Q /Matrix [1 0 0 1 0 0] >> q Q q >> /BBox [0 0 88.214 16.44] /Type /XObject /Resources<< /F3 17 0 R /FormType 1 393 0 obj endstream /ProcSet[/PDF/Text] BT /Length 79 /F3 12.131 Tf /Matrix [1 0 0 1 0 0] q /F4 12.131 Tf 1 i q q Q /Meta195 209 0 R >> endobj /Font << /Type /XObject q ET q [3] One half of a number increased by fourteen is twenty-one. 0 g /Meta359 373 0 R Q q >> Q q /F1 12.131 Tf 1.007 0 0 1.007 551.058 703.126 cm Q endobj /FormType 1 343 0 obj 1.005 0 0 1.007 102.382 293.596 cm stream endobj /Meta61 Do BT q /ProcSet[/PDF] BT stream /ProcSet[/PDF] 0 g BT /Type /XObject >> 20 0 obj /Meta247 Do q q Q /BBox [0 0 88.214 35.886] /ProcSet[/PDF] q 78 0 obj << 1.005 0 0 1.007 45.168 916.925 cm /Subtype /Form >> << BT stream << /ProcSet[/PDF/Text] /Subtype /Form 1 g 1.007 0 0 1.006 551.058 836.374 cm Q q /Type /XObject 549.694 0 0 16.469 0 -0.0283 cm endobj /FormType 1 stream ET 1 i >> >> /BBox [0 0 88.214 16.44] /Length 63 ET /FormType 1 /Meta408 Do 0 5.203 TD 0 g Q BT 1 i /Meta111 Do 722.699 473.519 l q Q << BT /Type /XObject 4 0 R 1 g Q /Matrix [1 0 0 1 0 0] /F3 12.131 Tf 37 0 obj 21 0 obj /Meta104 118 0 R /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] endstream /F1 7 0 R endobj (3) Tj q Q 0 G 0 g 1.014 0 0 1.007 531.485 383.934 cm Q 1.005 0 0 1.007 102.382 546.541 cm 0.786 Tc Q 1 g /BBox [0 0 673.937 68.796] Q /BBox [0 0 88.214 35.886] Q q endstream 1 i >> /Meta141 155 0 R >> /Resources<< endobj Q q /Meta288 302 0 R endobj /ProcSet[/PDF/Text] /Type /XObject q q /Matrix [1 0 0 1 0 0] (B) Tj endobj << /Subtype /Form >> endstream endstream 1.502 5.203 TD BT >> q 0.458 0 0 RG q /FormType 1 1 i /F4 12.131 Tf /Length 54 q /Contents [446 0 R] /XHeight 477 /Length 74 << 0 G 1.005 0 0 1.007 102.382 872.509 cm 405 0 obj 1.005 0 0 1.007 102.382 599.991 cm Q /Meta327 341 0 R 1.007 0 0 1.007 551.058 523.204 cm /ProcSet[/PDF/Text] >> 1 i 1 g q /Type /XObject /F3 17 0 R 1 i /Matrix [1 0 0 1 0 0] Q Q /F4 36 0 R Q ET endobj /Matrix [1 0 0 1 0 0] Q 1 i 0 g endobj 0 G 321 0 obj endobj q q stream q /Resources<< /F1 7 0 R q BT /Subtype /Form (6\)) Tj stream /FormType 1 /Subtype /Form 229 0 obj endstream /Resources<< 1 i /BBox [0 0 88.214 16.44] Q q 0.738 Tc /FormType 1 endobj /Matrix [1 0 0 1 0 0] 1 i q /Font << 0.737 w /F3 17 0 R /Length 16 q q q 0 0 0 778 611 709 774 611 556 0 0 0 0 0 0 0 Q /FormType 1 ET endstream /FormType 1 /F1 7 0 R stream /Matrix [1 0 0 1 0 0] endobj << endobj Q 0 g 0 g << /ProcSet[/PDF/Text] q /Resources<< 1.007 0 0 1.007 130.989 636.879 cm Q 306 0 obj 1 i << 0 g /ProcSet[/PDF] stream /BBox [0 0 30.642 16.44] << Q 9.723 5.336 TD endobj 1 of this study. 1 i >> Q /BBox [0 0 534.67 16.44] /Resources<< /Length 54 0 g /Meta330 344 0 R /Meta341 355 0 R /BBox [0 0 30.642 16.44] /FormType 1 /Resources<< 404 0 obj [tex]\sin (\pi -x)=\sin x[/tex]. q /Subtype /Form /F3 12.131 Tf Q /Subtype /Form /FormType 1 /Meta235 249 0 R /Resources<< q Q /Type /XObject /F3 12.131 Tf /Type /XObject /Length 59 >> Q Q << /FormType 1 /Meta418 Do 0 g >> 0.564 G 0.564 G Q 307 0 obj /Subtype /Form /Length 118 /Type /XObject q Q endstream q 357 0 obj endobj /Length 69 9 + x. fourteen decreased by a number p. 14 - p. seven less than a number t. t - 7. the product of 9 and a number n. /Meta161 Do << /BBox [0 0 15.59 16.44] /Meta331 Do 0 g >> endobj endstream /Type /XObject >> /Meta30 Do 1 i << /FormType 1 /ProcSet[/PDF/Text] >> endstream /FormType 1 /ProcSet[/PDF] /FormType 1 Q /Meta232 246 0 R Q 143 0 obj /Font << >> 153 0 obj q /Meta108 Do 3.742 5.203 TD 0 G q ET 1 g 1.502 5.203 TD >> /Meta304 318 0 R /Subtype /Form q /Matrix [1 0 0 1 0 0] /Meta157 171 0 R >> >> /FormType 1 q /Resources<< Q 313 0 obj 0 20.154 m 0 w q ET /Length 81 Q /Length 206 Q q Q >> /F3 17 0 R /Length 69 26.957 5.203 TD 1 i 0 5.203 TD /Length 60 /Length 59 >> q /Meta338 Do Q /FormType 1 1.007 0 0 1.006 411.035 690.329 cm 0.737 w Q >> Q /Matrix [1 0 0 1 0 0] /Font << /Meta30 43 0 R 0.564 G 1 i 1 i /Type /XObject Q Q /F4 12.131 Tf endobj /Length 60 /Matrix [1 0 0 1 0 0] endstream /Meta121 Do endstream (C\)) Tj 1.502 7.841 TD /Subtype /Form stream Q endobj /FormType 1 q 12.727 5.203 TD /Type /XObject /Resources<< BT 0 w q q 32 0 obj /Length 16 371 0 obj Q q /Subtype /Form /F3 17 0 R /Resources<< Q stream endstream stream /Meta180 Do /F4 12.131 Tf 1 i Q ET BT /FormType 1 /Font << Q 0 w Q q endobj q 0 G 389 0 obj 0 G Q /FormType 1 >> Q (-4) Tj 69 0 obj 309 0 obj endstream q 1 i 0.458 0 0 RG /FormType 1 /Length 12 /Meta307 321 0 R >> BT Q /FormType 1 /BBox [0 0 88.214 16.44] 1 i /Resources<< Let the 2nd number be y. 0 0 0 500 553 444 611 479 333 556 582 291 0 0 291 883 >> 1.014 0 0 1.007 111.416 330.484 cm /ProcSet[/PDF] q /Matrix [1 0 0 1 0 0] Q Q Q (x) Tj >> Q q endobj 1.007 0 0 1.007 411.035 330.484 cm /Meta236 250 0 R (-11) Tj /Type /XObject Q >> ET /Length 68 >> 197 0 obj /Font << 0 w ET Advertisement Answer No one rated this answer yet why not be the first? /FormType 1 0 g /F4 36 0 R q 0 G >> /Length 64 q /BBox [0 0 639.552 16.44] 0 w endstream q 1 g Q >> /Type /XObject q MetS-Z quartiles and their associated risks are presented in Fig. /F3 12.131 Tf 0.51 Tc 0 G Double or twice a number means 2x, and triple or thrice a number means 3x. 20.21 5.203 TD /F3 12.131 Tf /Meta280 Do /F3 17 0 R Q 1 i >> 0.458 0 0 RG endobj S endobj /Length 70 /Matrix [1 0 0 1 0 0] /Resources<> /F3 17 0 R /F3 12.131 Tf Twice a number would be 2x. 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